Make Wordle in Python terminal in about 48 lines of code

Table of Content

1. Setup Enviorment
2. Setting the template and Intro function
3. Input and word logic cases
4. Word guess logic
5. Use a text file instead of a word list

Image of Final Project, Wordle in Terminal

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• VS code
• Python

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What is Wordle and what does it need?

Wordle is a word guessing game, that the user guess a random word and get clues based on past guess

So some things we will need, randomness, and a word bank and game logic.

import random

words = ['gamed', 'usfgdc', 'tired', 'cofee', 'ineed']

def main():

main()

Probably a good idea to include some Instructions to the game at the top, so lets add a function

def Intro():
    print("This is Wordle")
    print("\t✅ - letter is the word and is in correct spot")
    print("\t🟨 - letter is the word and is not in the right spot")
    print("\t _ - letter is not in the word")
    print()

Call the function in your main

import random

words = ['gamed', 'usfgdc', 'tired', 'cofee', 'ineed']

def Intro():
    ...

def main():
    Intro()
    
main()

Picking a random word in the word bank

def main():
    Intro()
    hiddenWord = words[random.randint(0, len(words)-1)]

Also wordle has a limited number of trys, so lets add that too.

hiddenWord = words[random.randint(0, len(words)-1)]
attempts = 5    # NEW CODE HERE

Duration 0:07:00

Design and Logic

What we want:

• While user still has an attempt left, allow them to guess
• Take the user's input/guess
• If User guess the hidden word then end game, Otherwise do some wordle game logic to give a glue
• Remove an attempt per guess and tell the player

def main():
    Intro()
    hiddenWord = words[random.randint(0, len(words)-1)]
    attempts = 5

    # NEW CODE HERE
    while (attempts > 0):
        guess = input("Enter Guess (5 Letter Word): ").lower()

        if (guess == hiddenWord):
            print("Good Guess!!!")
            break
        else:
            # Do wordle clue logic
        
        attempts -= 1
        print(f"{attempts} are left.\n")

Design and Logic

• Create an output that tells us something about the hidden word
• Check for every letter in the guess If it is in the same spot of the hidden word, give it a checkmark
• else if the letter is in the word, mark it as yellow
• otherwise leave it blank

Doing it in code

if (guess == hiddenWord):
    print("Good Guess!!!")
    break
else:
    # NEW CODE HERE
    output = ""
    for hiddenLetter, guessLetter in zip(hiddenWord, guess):
        if (hiddenLetter == guessLetter.lower()):
            output += " ✅ "

Since if statements will skip else-if and else statements when true, we can just stack these statements logically for easy implementation

else:
    output = ""
    for hiddenLetter, guessLetter in zip(hiddenWord, guess):
        if (hiddenLetter == guessLetter.lower()):
            output += " ✅ "

        # NEW CODE HERE
        elif (guessLetter in hiddenWord):
            output += " 🟨 "
        else:
            output += " _ "

    print(output)       #outside of the loop

Lets reveal the secret word if user run out of attempts

            attempts -= 1
            print(f"{attempts} are left.\n")

# NEW CODE HERE
            if (attempts == 0): 
                print(f"All attempts were used, the word was {hiddenWord.upper()}.")
# NEW CODE END

main()

Now Your wordle is already functional logically, HOORAY

However, you may notice that you can enter non-real words and it still runs unlike wordle

Additionally, you also may realize that if we want more words, we will have to expand our list which makes it ugly and wonder why do that manually

Design and Logic

• Make it so that we can not guess random letters, and actually have to guess words
• Not take User's attempt or run logic not in our word bank
• Make it so that our word bank can be larger without bad code

Coding our Design

while (attempts > 0):
    guess = input("Enter Guess (5 Letter Word): ").lower()

    # NEW CODE HERE
    if (guess not in words):            # because we are arrogant if we dont know it, it doesn't exist
        print("Word not in word list, Try another word\n")
        continue
    # NEW CODE END

    if (guess == hiddenWord):
            print("Good Guess!!!")

Opening an external file in python

import random

# NEW CODE HERE
# wordslist.txt was taken from here https://gist.github.com/dracos/dd0668f281e685bad51479e5acaadb93
with open('wordslist.txt', 'r') as wordsFile:
    words = wordsFile.read().split('\n')

# words = ['gamed', 'usfgdc', 'tired', 'cofee', 'ineed']        Remove this if you want

Optional, Rather than having Colored squares you can have colored text by replaceing the logic part with this code

if (hiddenLetter == guessLetter.lower()):
    output += "\033[32m " + guessLetter.upper()
elif (guessLetter in hiddenWord):
    output += "\033[33m " + guessLetter.upper()
else:
    output += "\033[37m"+ " _ "

output += "\033[37m"

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